Respuesta :

Answer:

y = - [tex]\frac{10}{3}[/tex] x - 23

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 9, 7 ) and (x₂, y₂ ) = (- 6, - 3 )

m = [tex]\frac{-3-7}{-6-(-9)}[/tex] = [tex]\frac{-10}{-6+9}[/tex] = [tex]\frac{-10}{3}[/tex] = - [tex]\frac{10}{3}[/tex] , then

y = - [tex]\frac{10}{3}[/tex] x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (- 6, - 3 ) , then

- 3 = 20 + c ⇒ c = - 3 - 20 = - 23

y = - [tex]\frac{10}{3}[/tex] x - 23 ← equation of line

Answer:

y= -10x/3 + 1

Step-by-step explanation:

gradient of a line= (Y2-Y1)/(X2-X1)

= (-3-7)/[-6-(-9)]

=-10/3

equation of a line

(Y-Y1)/(X-X1)= gradient

(Y-7)/(X+9)= -10/3

3(Y-7)= -1d0(X+9)

3y-21= -10x -19

3y= -10x + 3

dividing both sides by 3

y= -10x/3 + 1