stacie, who has a mass of 45 kg, starts down a slide that is inclined at an angle of 45 degree with the horizontal. If the coefficient of kinetic friction between stacie's shorts and the slide is 0.25, what is her acceleration

Respuesta :

The acceleration of the mass sliding along the horizontal surface is 5.2 m/s².

The given parameters;

  • mass of the crate, m = 45 kg
  • angle, = 45 degrees
  • coefficient of kinetic friction, = 0.25

The acceleration of the mass is calculated by determining the net force on the mass as shown below;

[tex]\Sigma F_{net} = ma\\\\Wsin\theta - F_k = ma\\\\mg sin\theta - \mu_k F_n = ma\\\\mg sin\theta - \mu_k mg\ cos\theta = ma\\\\g sin\theta - \mu_k g\ cos\theta = a\\\\g(sin\theta - \mu_k \ cos\theta ) = a\\\\9.8(sin\ 45 \ - \ 0.25\times cos \ 45) = a\\\\9.8(0.53) = a\\\\5.2 \ m/s^2 = a[/tex]

Thus, the acceleration of the mass sliding along the horizontal surface is 5.2 m/s².

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