Answer:
A) (-1,3) and (4,3)
B) (-1,-7) and (4,-7)
C) (1.5, .5) and (1.5, -4.5)
Step-by-step explanation:
For 1 and 2, because the y-values of the points are the same, the length of the square can be found by subtracting the x-coordinates.
4-(-1)=4+1=5
The length of the side of the square is 5.
1. For the first set of points, the square is above the two given points so just add 5 to the y-values
-2+5=3
This gives you the points:
(-1,3) and (4,3)
2. For the second set of points, the square is below the two given points so subtract 5 from the y-values.
-2-5=-7
This give you the points:
(-1,-7) and (4,-7)
3. The third answer is when the two given points are on opposite corners
of the square.
Here the diagonal is equal to 5 since they are on opposite corners of the square.
The diagonal of a square can be found with the pythagorean theorem
Since we have the diagonal we can find the side lengths we need.
[tex]2s^2=25[/tex]
s=[tex]\sqrt{\frac{25}{2} }[/tex]
s=3.5355
We want the new vertices to be in the middle of the other vertices x-coordinates
[tex]\frac{4-(-1)}{2} =\frac{5}{2} =2.5[/tex]
The new vertices will be 2.5 units away from the other vertices
-1+2.5=1.5
The new vertices will be at x=1.5
Now we need the pythagorean theorem again to find the y-values
[tex](2.5)^2+h^2=(3.5355)^2[/tex]
[tex]6.25+h^2=\frac{25}{2}[/tex]
[tex]h=\sqrt{\frac{25}{2} -6.25}[/tex]
h=2.5
The new vertices will be:
(1.5, -2+2.5)=(1., .5)
(1.5, -2-2.5)=(1.5, -4.5)
