If 20.3 g of NO and 13.8 g of O₂ are used to form NO₂, how many moles of excess reactant will be left over?
2 NO (g) + O₂ (g) → 2 NO₂ (g)

Respuesta :

Answer:

0.02 moles of O₂ will be leftover.

Explanation:

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