The magnitude of the net force exerted by the three astronauts is 84.5 N and the rate at which the asteroid's velocity changes is 0.845 m/s².
The given parameters;
The resultant horizontal force applied by the three astronauts on the asteroid is calculated as;
Fₓ = 35cos(45) + 35cos(45) + 35cos(0)
Fₓ = 84.5 N
The rate at which the asteroid's velocity changes is calculated as;
[tex]F = ma = m\frac{\Delta v}{\Delta t} \\\\\frac{\Delta v}{\Delta t} = \frac{F}{m} \\\\\frac{\Delta v}{\Delta t} = \frac{84.5}{100} \\\\\frac{\Delta v}{\Delta t} = 0.845 \ m/s^2[/tex]
Thus, the magnitude of the net force exerted by the three astronauts is 84.5 N and the rate at which the asteroid's velocity changes is 0.845 m/s².
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