Respuesta :
Explanation:
According to Boyles law
[tex]pressure \: \alpha \frac{1}{volume} [/tex]
P1V1 = P2V2
205 (4) = P2 (12)
[tex]P2 = \frac{205 \times 4}{12} [/tex]
P2= 820/12
P2= 68.3 KPa
The pressure in the container after the expanssion of gas, if the temperature remains constant is 68.3 kPa.
What is Boyle's Law?
According to the Boyle's Law, at constant temperature pressure of any gas is inversely proportional to the volume of the gas, i.e.
P ∝ 1/V
Required equation for the calculation of the pressure is:
P₁V₁ = P₂V₂, where
P₁ = initial pressure = 205 kPa
V₁ = initial volume = 4 L
P₂ = final pressure = ?
V₂ = final volume = 12 L
On putting all these values on the above equation, we get
P₂ = (205)(4) / (12) = 68.3 kPa
Hence resultant pressure is 68.3 kPa.
To know more about Boyle's Law, visit the below link:
https://brainly.com/question/469270