[tex]\\ \bull\tt\dashrightarrow Slope=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
[tex]\\ \bull\tt\dashrightarrow Slope=\dfrac{2-4}{0+6}[/tex]
[tex]\\ \bull\tt\dashrightarrow Slope=\dfrac{-2}{6}[/tex]
[tex]\\ \bull\tt\dashrightarrow Slope=\dfrac{-1}{3}[/tex]
Answer:
Step-by-step explanation:
Line through ( – 6, 4) and (0,2) has a slope:
The line perpendicular to this has a slope, negative-reciprocal to this: