Answer:
-2x^2-8x+12
Step-by-step explanation:
f(x)=3x^2-2x+4
g(x)=5x^2+6x-8
(f-g) (x)= 3x^2-2x+4 - (5x^2+6x-8)
Distribute the minus sign
(f-g) (x)= 3x^2-2x+4 - 5x^2-6x+8
Combine like terms
=-2x^2-8x+12
[tex] - 2( {x}^{2} - 4x + 6)[/tex]
[tex] f(x)=3x^2-2x+4 \\ g(x)=5x^2+6x-8 \\ (f-g) (x) = 3 {x}^{2} - 2x + 4 - (5 {x}^{2} + 6x - 8) \\ = 3 {x}^{2} - 2x + 4 - 5 {x}^{2} - 6x + 8 \\ = - 2 {x}^{2} - 8x + 12 \\ = - 2( {x}^{2} - 4x + 6)[/tex]
