Using the factor theorem, it is found that the polynomial is:
[tex]f(x) = x^3 - 2x^2 - 3x + 6[/tex]
Given by the first option
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Given a polynomial f(x), this polynomial has roots [tex]x_{1}, x_{2}, x_{n}[/tex] using the factor theorem it can be written as: [tex]a(x - x_{1})*(x - x_{2})*...*(x-x_n)[/tex], in which a is the leading coefficient.
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In this question:
- [tex]x_1 = 2[/tex]
- [tex]x_2 = \sqrt{3}[/tex]
- [tex]x_3 = -\sqrt{3}[/tex]
- By the options, leading coefficient [tex]a = 1[/tex]
Thus:
[tex]f(x) = (x - 2)(x - \sqrt{3})(x + \sqrt{3})[/tex]
[tex]f(x) = (x - 2)(x^2 - 3)[/tex]
[tex]f(x) = x^3 -2x^2 - 3x + 6[/tex]
Which is the polynomial.
A similar problem is given that: https://brainly.com/question/4786502
