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A voltaic cell prepared using zinc andiodine has the following cell notation.

Zn(s) | Zn2+(aq) ||I-(aq) | I2(s) |C(graphite)

Which of the following equations correctly represents the balanced,spontaneous, cell reaction?

a. 2I-(aq) +Zn2+(aq) --->I2(s) + Zn(s)
b. I2(s) + Zn(s)---> 2I-(aq) +Zn2+(aq)
c. 2I-(aq) + Zn(s)---> I2(s) +Zn2+(aq)
d. I2(s) +Zn2+(aq) --->2I-(aq) + Zn(s)
e. None of the above, since graphite must be in the equation.

Respuesta :

DALAU

Answer:

b. I2(s) + Zn(s)---> 2I-(aq) +Zn2+(aq)

Explanation:

Firstly, you can rule out any equation that doesn't have a balanceof charges outright. Therefore, the third and fourthquestions are silly. Graphite is generally regarded as an'inert' electrode, meaning that it will not react in a voltaiccell. This leaves only the first or the second as a viableanswer.

Logically, iodide and zinc in solution will not spontaneously formtheir elements.

This leaves only the second choice as a viable answer.

I2(s) + Zn(s)---> 2I-(aq) +Zn2+(aq)

is the correct choice.

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