Answer:
answer 6
Step-by-step explanation:
It has been a long time that i have done that!
[tex]\int\limits^3_2 {\int\limits^2_0 {(4-y^2)} \, dy} \, dx \\\\\\=\int\limits^3_0 {(4-y^2)} \, dy*(2-0)\\\\=2*[4y-\dfrac{y^3}{3} ]^3_0\\\\=2*(12-9)\\\\=6\\[/tex]
