In a quadrilateral HELP, HE is congruent to LP. What other condition would prove that HELP is a parallelogram?

In a quadrilateral HELP HE is congruent to LP What other condition would prove that HELP is a parallelogram class=

Respuesta :

Answer:

[tex]HE || LP[/tex]

Step-by-step explanation:

Given

[tex]HE \cong LP[/tex]

Required

Which proves that [tex]HELP[/tex] is a parallelogram

We have:

[tex]HE \cong LP[/tex]

The given sides must also be parallel i.e.

[tex]HE || LP[/tex]

Hence, (c) is correct