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A polynomial p has zeros when x = 5, x = -1, and x = -1/4
What could be the equation of p?
A. p(x) = (x +5)(x + 1)(4x + 1)
B. p(x) = (x - 5)( x + 1)(4x + 1)
C. p(x) = (x + 5)(x - 1)(4x - 1)
D. p(x) = (5x)(-1x)( - 1/4x)

A polynomial p has zeros when x 5 x 1 and x 14 What could be the equation of p A px x 5x 14x 1 B px x 5 x 14x 1 C px x 5x 14x 1 D px 5x1x 14x class=

Respuesta :

Answer:

[tex]x=5[/tex]  ⇒  [tex](x-5)=0[/tex]

[tex]x=-1[/tex]  ⇒[tex](x+1)=0[/tex]

[tex]x=-1/4[/tex] ⇒ [tex](x+1/4)=0[/tex] ⇒ [tex](4x+1)=0[/tex]

[tex]p(x)=(x-5)(x+1)(4x+1)=0[/tex]

[tex]Option(B)[/tex]

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Hope it helps...

Have a great day!!

wegnerkolmp2741o

Answer:

p(x) =  (x-5) (x+1)(4x+1)

Step-by-step explanation:

We know the equation for a polynomial with zeros is written as

f(x) = a( x-b1) (x-b2)...... where b are the zeros

We have zeros x = 5, x = -1, and x = -1/4

p(x) = a( x-5) (x- -1) (x - -1/4)

p(x) = a (x-5) (x+1) (x+1/4)

Let a = 4

p(x) = 4 (x-5) (x+1) (x+1/4)

p(x) =  (x-5) (x+1)(4x+1)

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