Answer: [tex]x<-8[/tex]
Step-by-step explanation:
The given inequality : [tex]3-(2x-5)<-4(x+2)[/tex]
To solve the inequality for x , first we open the parenthesis , we get
[tex]3-2x+5<-4x+(-4)2[/tex]
[tex]\Rightarrow\ 3-2x+5<-4x-8[/tex] [Note : (-)(+)=(-)]
[tex]\Rightarrow\ 3+5-2x<-4x-8[/tex]
[tex]\Rightarrow\ 8-2x<-4x-8[/tex]
Add 4x on both sides , we get
[tex]8-2x+4x<-4x-8+4x[/tex]
[tex]8+2x<-8[/tex]
Subtract 8 from both sides , we get
[tex]2x<-16[/tex]
Divide both sides by 2 , we get
[tex]x<-8[/tex]
Hence, the correct answer is : [tex]x<-8[/tex]
