contestada

Bradley and Kelly are out flying kites at a park one afternoon. A model of Bradley and Kelly's kites are shown below on the coordinate plane as kites BRAD and KELY, respectively:

Which statement is correct about the two kites?

They are similar because Segment BR to segment DB is 1:2 and Segment KE to segment YK 1:2.

They are not similar because Segment BR to segment DB is 1:5 and Segment KE to segment YK is 1:2.

They are not similar because Segment BR to segment DB is 1:2 and Segment KE to segment YK is 1:5.

They are similar because Segment BR to segment DB is 1:5 and Segment KE to segment YK is 1:5.

Bradley and Kelly are out flying kites at a park one afternoon A model of Bradley and Kellys kites are shown below on the coordinate plane as kites BRAD and KEL class=

Respuesta :

3rd answer. They are not similar because BR-DB has a larger ratio then KE-YK. Similar means the corresponding sides have the same ratios between 2 shapes. The sides do not.
frika

1. The vertices B, D and R have coordinates (9,9), (1,5) and (11,5), respectively. Then

[tex] BR=\sqrt{(11-9)^2+(5-9)^2}=\sqrt{4+16} = 2\sqrt{5} ,\\BD=\sqrt{(1-9)^2+(5-9)^2}=\sqrt{64+16} = 4\sqrt{5}. [/tex]

The ratio

[tex] \dfrac{BR}{BD}= \dfrac{2\sqrt{5}}{4\sqrt{5}} =\dfrac{1}{2}. [/tex]

2. The vertices K, E and Y have coordinates (13,9), (14,10) and (14,2), respectively. Then

[tex] KE=\sqrt{(13-14)^2+(9-10)^2}=\sqrt{1+1} = \sqrt{2} ,\\KY=\sqrt{(13-14)^2+(9-2)^2}=\sqrt{1+49} = 5\sqrt{2}. [/tex]

The ratio

[tex] \dfrac{KE}{KY}= \dfrac{\sqrt{2}}{5\sqrt{2}} =\dfrac{1}{5}. [/tex]

Answer: correct answer is C (they are not similar because segment BR to segment DB is 1:2 and segment KE to segment YK is 1:5.)