[tex]\frac{245 g SO2 }{} \frac{1 mol SO2 }{64.07 g SO2} \frac{1 mol H2SO3}{1 mol SO2 } \frac{82.09 g H2SO3}{1 mol H2SO3} =314 g H2SO3[/tex]
Step-by-step explanation:
2) What mass of Sulfurous acid is produced, when 245g of Sulfur Dioxide is
reacted with water?
H2O + SO2 → H2SO3
↓ ↑
mol → mol
SO2 H2SO3
\frac{245 g SO2 }{} \frac{1 mol SO2 }{64.07 g SO2} \frac{1 mol H2SO3}{1 mol SO2 } \frac{82.09 g H2SO3}{1 mol H2SO3} =314 g H2SO3
