The quadratic equation for his flight path is y = a(x² - 32x + 156) where a is a constant if the Blue bird began at location (6,0) and hit the ground at (26,0).
Any equation of the form [tex]\rm ax^2+bx+c=0[/tex] Where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.
We know the standard form of a quadratic function:
y = ax² + bx + c
Plug x = 6 and y = 0
0 = 36a + 6b + c ...(1)
Plug x = 26, and y = 0
0 = 676a + 26b + c ...(2)
From the equation (1) and equation (2) find the value of b and c
b = -32a
c = 156a
Plug this values in the standard form of a quadratic equation:
y = ax² + (-32a)x + 156a
y = a(x² - 32x + 156)
The above quadratic equation represents the flight path.
Let's take the value of a = -1
y = -1(x² - 32x + 156) (refer attached picture for the path of the graph)
Thus, the quadratic equation for his flight path is y = a(x² - 32x + 156) where a is a constant if the Blue bird began at location (6,0) and hit the ground at (26,0).
Learn more about quadratic equations here:
brainly.com/question/2263981
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