Answer:
[tex]\frac{3}{5}[/tex]
Step-by-step explanation:
GIVEN :-
- Measure of side opposite to ∠A (Perpendicular) = 6 units
- Measure of side adjacent to ∠A (Base) = 8 units
TO FIND :-
FACTS TO KNOW BEFORE SOLVING :-
- [tex]Hypotenuse = \sqrt{(Base)^2 + (Perpendicular)^2}[/tex]
- [tex]\sin A = \frac{Side \: opposite \: to \: A}{Hypotenuse}[/tex]
PROCEDURE :-
Measure of perpendicular of triangle = 6 units
Measure base of triangle = 8 units
Measure of Hypotenuse = [tex]\sqrt{(6)^2 + (8)^2} = \sqrt{36 + 64} = \sqrt{100} = 10 \: units[/tex]
Side opposite to ∠A = Perpendicular of triangle = 6 units
∴ sin A = [tex]\frac{6}{10} = \frac{3}{5}[/tex]
