Answer:
The answer is "[tex]44 \ m^2[/tex]"
Step-by-step explanation:
[tex]R=4.5 \ m \\\\r=2.5\ m\\\\[/tex]
The area between two concentrated circles via an exterior circle radius R and an internal circle
[tex]r =\pi(R^2-r^2)[/tex]
The region, therefore, consists of two concentrated circles with radii of 4.5 m and 2.5 m.
[tex]r=\pi(4.5^2 -2.5^2)\\\\[/tex]
[tex]=\frac{22}{7} (20.25-6.25) \\\\ =\frac{22}{7} (14) \\\\=22 \times 2 \\\\ =44 \ m^2[/tex]
