evaluate each function in the table for f(3)

Answer:
Function 1:
We have 3x + 5, so we plug in 3 for x to get 9 + 5 = [tex]\boxed{14}[/tex]
Function 2:
We have [tex]\frac{1}{2}x^{2} - 1.5[/tex] so we have 4.5 - 1.5 = [tex]\boxed{3}[/tex]
Function 3:
We have [tex]\frac{3}{2x}[/tex] which becomes [tex]\frac{3}{6} = \boxed{\frac{1}{2}}[/tex].