Answer:
The correct answer is - 10.6666 channels.
Explanation:
Given:
numbers of clusters duplicated = 16 times
The frequency bands for mobile unit transmission are - 825 to 845 MHz
The frequency bands for base station transmission = 870 to 890 MHz
The required bandwidth for each one-way direction of channels = 30 kHz
Formula:
the number of simultaneous communications that can be supported by each system [tex]k_{sys}[/tex] = [tex]MB_{CL}[/tex]/[tex]b_{ch}[/tex]
Solution:
The required bandwidth for each two-way direction of channels = 2 × 30 kHz
then, according to the formula the number of simultaneous communications that can be supported by each system
[tex]k_{sys}[/tex] = [tex]MB_{CL}[/tex]/[tex]b_{ch}[/tex]
k_{sys} = 16×40/60
[b_{ch} = (845-825) + (890-870) = 20+20=40)]
= 10.6666.
