I need the length of AC to the nearest 10th. If you can explain how you got it, that will be nice, but you don’t have too

Answer:
13.5
Step-by-step explanation:
[tex]\sin 64\degree = \frac{AC}{AB}\\\\AC = AB \sin 64\degree \\\\AC = 13.481910694\\\\AC \approx 13.5[/tex]