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How many moles of acetic acid and of sodium acetate are present in 50.0 mL of solution?

We calculate it as follows:

moles of acetic acid = .120 mol/L (.050 L ) = 0.006 mol
moles of sodium acetate = 0.150 mol/L (0.050 L) = 0.008 mol

Hope this answers the question. Have a nice day.

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