Answer:
[tex]L=480\ kg-m^2/s[/tex]
Step-by-step explanation:
Given that,
Mass of a person, m = 80 kg
The distance from the centre of the platform, r = 2 m
The tangential speed of the platform, v = 3 m/s
We need to find the angular momentum of the person. The formula for the angular momentum is given by :
[tex]L=mvr\\\\L=80\times 3\times 2\\\\L=480\ kg-m^2/s[/tex]
So, the required angular momentum is equal to [tex]480\ kg-m^2/s[/tex].
Answer:
Tangential speed is 0.68 m/s
Explanation:
It is given that,
Mass of the beetle, m = 0.023 kg
It is placed at a distance of 0.15 m from the center of record i.e. r = 0.15 m.
If it takes 0.070 n of force to keep the beetle moving in a circle on the record i.e. centripetal force acting on it is, F = 0.070 N
We have to find the tangential speed of the beetle. The formula for centripetal force is given by :
v is tangential speed
v = 0.675 m/s
or
v = 0.68 m/s
Hence, the correct option for tangential speed is (A).
Step-by-step explanation:
