Answer:
[tex]V_2=45.7mL[/tex]
Explanation:
Hello there!
In this case, since the equation to deal with dilution process involves the initial and final concentration and volume:
[tex]C_1V_1=C_2V_2[/tex]
Thus, given the initial and final concentrations and the initial volume, we can write:
[tex]V_2=\frac{C_1V_1}{C_2} =\frac{0.50M*147.1mL}{1.61M}\\\\V_2=45.7mL[/tex]
Best regards.
