need help for geoooooooooo

Given :
Since triangle AFB is congruent to triangle DEC their corresponding parts will be equal.
Which means :
Sum of all angles of a triangle = 180°
Measure of ∠CDE :
[tex] = \tt180 - 37 + 90[/tex]
[tex] = \tt180 - 127[/tex]
[tex] = \tt53[/tex]
Therefore, m∠A = 53°
[tex]\hookrightarrow\boxed{\color{plum}\bold {\tt \: \bold{m∠A = 53°}}}[/tex]