Given that,
The side length of a square garden [tex]=12\dfrac{2}{3}\ \tet{feet}=\dfrac{38}{3} \text{feet}[/tex]
A farmer plants squash in a garden with a perimeter of 50 1/2 feet = 50.5 feet
To find,
Which garden has a greater perimeter.
Solution,
The area of a square is given by :
A = 4s, s is side of square
A farmer plants beets, the perimeter is :
[tex]A=4\times \dfrac{38}{3}\\\\=50.67\ cm[/tex]
Hence, the square garden with side lengths 12 2/3 feet will have more perimeter.
