Which of the following functions has an initial value of 3/2 and a rate of change of -2/3?
A. y=2/3x+3/2
B. y=−3/2x−2/3
C. y=3/2x−2/3
D. y=−2/3x+3/2

Respuesta :

Answer:

The right answer is Option D: [tex]y = -\frac{2}{3}x+\frac{3}{2}[/tex]

Step-by-step explanation:

Given that initial value of 3/2 and rate of change is -2/3

The given functions can be observed and it can be concluded that the functions are in the form

[tex]y = mx+c[/tex]

Here m is the slope which is also called rate of change and c is the y-intercept.

The y-intercept is the initial value when input is zero.

So we have to look for a function that has 3/2 in place of c and -2/3 in place of m.

From the given options,

[tex]y = -\frac{2}{3}x+\frac{3}{2}[/tex] is the matching function

Hence,

The right answer is Option D: [tex]y = -\frac{2}{3}x+\frac{3}{2}[/tex]