A 12 V battery applies a potential difference to three resistors in series. If the potential at point P is 0.0 V, the potential at point B is:

Respuesta :

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Answer:

the potential at point B is 5 V, Option d) is the correct answer

Explanation:

Given that;

from the image;

R = 3 + 4 + 5 = 12 Ω

so I = 12/12 = 1 A

Q = 0 + 12 = 12 V

now

VA - VQ = - I × 3 = -3 V

VA = VQ - 3 =  12 - 3 = 9 V

VB - VA = - I × 4Ω = - 4 V

⇒VB = VA - 4 = 9 V - 4 V = 5 V

Therefore the potential at point B is 5 V

Option d) is the correct answer

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