Answer:
The mass of ammonia (NH3) that contains [tex]1.00 \times 10^12[/tex] hydrogen atoms is [tex]9.4\times 10^{-12}[/tex] g.
Explanation:
As [tex]6.022\times 10^{23}[/tex] atoms of hydrogen = 1 mole of the hydrogen atom
Therefore, [tex]10^{12}[/tex] atoms of hydrogen [tex]= \frac{1}{6.022 \times 10^{23}}\times 10^{12}=1.66\times 10^{-12}[/tex] moles of the hydrogen atom.
Now, there are 3 moles of hydrogen atoms in 1 mole of ammonia [tex](NH_3)[/tex].
As the mass of 1 mole of ammonia is 17g, so
when there are 3 moles of hydrogen atoms, then the mass of ammonia = 17 g
Therefore, when there are [tex]1.66\times 10^{-12}[/tex] moles of hydrogen atoms, then the mass of ammonia [tex]= \frac{17}{3}\times 1.66\times 10^{-12}=9.4\times 10^{-12[/tex] g.
Hence, the mass of ammonia [tex](NH_3)[/tex] that contains [tex]1.00 \times 10^12[/tex] hydrogen atoms is [tex]9.4\times 10^{-12}[/tex] g.
