Answer:
The magnitude of the final velocity of the water balloon is 84.3 m/s.
Explanation:
To calculate the velocity of the water balloon when it strikes the ground we need to use the next equation:
[tex] v_{f}^{2} = v_{0}^{2} - 2gh [/tex]
Where:
[tex]v_{f}[/tex]: is the final velocity =?
[tex]v_{0}[/tex]: is the initial velocity = 2 m/s
g: is the gravity = 9.81 m/s²
h: is the height = 4.5 m
By entering the above values into equation (1) we have:
[tex] v_{f}^{2} = v_{0}^{2} - 2gh = (2 m/s)^{2} - 2*9.81 m/s^{2}*4.5 m = -84.3 m/s [/tex]
The minus sign is because the direction of the velocity vector is in the negative vertical axis.
Therefore, the magnitude of the final velocity of the water balloon is 84.3 m/s.
I hope it helps you!
