the value of 'h' used to solve the equation by completing the square method is [tex]\frac{9}{4}[/tex]
Given :
An equation and the first step in its solution are shown.
Equation: [tex]x^2 + 3x -9 = 0[/tex]
Step 1: [tex]x^2 + 3x + h = 9 + h[/tex]
In completing the square method , we take the coefficient of x and divide it by 2 and then square it
coefficient of x is 3
divide it by 2 , so we get [tex]\frac{3}{2}[/tex]
Then we square it [tex](\frac{3}{2} )^2\\\frac{9}{4}[/tex]
Then we add it on both sides of the equation
[tex]x^2 + 3x + \frac{9}{4} = 9 + \frac{9}{4}[/tex]
So, the value of 'h' used to solve the equation by completing the square method is [tex]\frac{9}{4}[/tex]
Learn more : brainly.com/question/10662834
