Lines QS and NR intersect at P. Ray PM is perpendicular to line SQ.
What is the value of y?

Answer:
A. 13
Step-by-step explanation:
[tex] (6y - 14) + 90 + (2y) = 180 [/tex] (angles on a straight line)
Solve for y
[tex] 6y - 14 + 90 + 2y = 180 [/tex]
Collect like terms
[tex] 6y + 2y - 14 + 90 = 180 [/tex]
[tex] 8y + 76 = 180 [/tex]
Subtract 76 to both sides
[tex] 8y + 76 - 76 = 180 - 76 [/tex]
[tex] 8y = 104 [/tex]
Divide both sides by 8
[tex] \frac{8y}{8} = \frac{104}{8} [/tex]
[tex] y = 13 [/tex]