This question can be solved using the concepts of Newton's Law of Gravitation, and gravitational force.
The gravitational force between the two objects if the mass of each object is reduced to one-third of its original mass will be "A. 400 N".
According to Newton's Law of Gravitation the gravitational force between two objects is given as follows:
[tex]F = \frac{Gm_1m_2}{r^2}[/tex]---------- eqn (1)
where,
F = Gravitational force between objects = 3600 N
G = Universal gravitational constant
m₁ = mass of the first object
m₂ = mass of the second object
r = distance between the objects
Now, the masses have become one-third of the original value:
[tex]F'=\frac{G(\frac{m_1}{3})(\frac{m_2}{3})}{r^2}\\\\F' = \frac{1}{9}\frac{Gm_1m_2}{r^2}\\\\using\ eqn\ (1):\\\\F' = \frac{F}{9} = \frac{3600\ N}{9}\\\\[/tex]
F' = 400 N
Learn more about Newton's Law of Gravitation here:
brainly.com/question/17931361?referrer=searchResults
The attached picture illustrates Newton's Law of Gravitation.
