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Hooke's law states that the force, F, in a spring extended by a length x is given by
F=-kx. According to Newton's second law F = ma, where m is the mass and a is
the acceleration. Calculate the dimension of the spring constant k.​

Respuesta :

mathmate

Answer:

dimensions of k are  kg / s^2

Explanation:

F=ma   (Newton's second law)

F=-kx   (Hooke's law)

so equate both

-kx = ma

k = -ma/x

= mass * acceleration / distance  (dimensions, -1 has no dimension)

= kg * m/s^2 / m

= kg / s^2

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