Answer:
[tex]p(0) + p(1) = 2[/tex]
Step-by-step explanation:
=> [tex]p(x) = x^3-x^2+1[/tex]
Putting x = 0 in p(x)
=> [tex]p(0) = (0)^3-(0)^2+1[/tex]
=> [tex]p(0) = 0-0+1[/tex]
=> [tex]p(0) = 1[/tex]
Putting x = 1 in p(x)
=> [tex]p(1) = (1)^3-(1)^2+1[/tex]
=> [tex]p(1) = 1-1+1[/tex]
=> [tex]p(1) = 1[/tex]
So,
=> [tex]p(0)+p(1) = 1+ 1[/tex]
=> [tex]p(0) + p(1) = 2[/tex]
