Which function is the inverse of f Superscript negative 1 Baseline (x) = negative one-half x minus three-halves? f Superscript negative 1 Baseline (x) = one-half x minus three-halve

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Answer:

The answer is f-1(x)=1/2x-3/2

Step-by-step explanation:

I just took the test.

Two functions f(x) and g(x) are inverses if and only if:

f(g(x)) = x

g(f(x)) = x

We will find that the anwer here is g(x) = -2*x - 3

We want to find the inverse function of

[tex]f(x) = -\frac{1}{2} x - \frac{3}{2}[/tex]

Because f(x) is a linear function, its inverse is also a linear function, so at the moment we can write:

[tex]g(x) = a*x + b[/tex]

The composition will be:

[tex]g(f(x)) = a*(-\frac{1}{2}x - \frac{3}{2} ) + b = x[/tex]

Now we can expand the above expression to find the values of a and b.

[tex]g(f(x)) = a*(-\frac{1}{2}x - \frac{3}{2} ) + b = x\\\\ = -\frac{a}{2}*x - \frac{3*a}{2} + b = x\\\\[/tex]

Then we must have:

[tex]\frac{-a}{2} = 1\\\\a = -2[/tex]

and

[tex]\frac{-3a}{2} + b = 0\\b = \frac{3a}{2} = \frac{3*(-2)}{2} = -3[/tex]

Then the inverse function is:

g(x) = -2*x - 3

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