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Consider the reaction 2 CO + O2 → 2 CO2 .What is the percent yield of carbon dioxide

(MW = 44 g/mol) if the reaction of 10 g of carbon monoxide (MW = 28 g/mol) with

excess O2 produces 8 g of carbon dioxide? Answer in units of %.

Respuesta :

sebassandin

Answer:

[tex]Y=50.9\%[/tex]

Explanation:

Hello,

In this case, given the reaction, we can directly compute the theoretically yielded grams of carbon dioxide, considering the 2:2 molar ratio between carbon monoxide (molar mass = 28 g/mol) and carbon dioxide (molar mass = 44 g/mol) and the initial reacting grams of carbon monoxide in excess oxygen:

[tex]m_{CO_2}^{theoretical}=10gCO*\frac{1molCO}{28gCO}*\frac{2molCO_2}{2molCO}*\frac{44gCO_2}{1molCO_2} =15.7gCO_2[/tex]

Thus, as only 8 g were actually yielded, we compute the percent yield:

[tex]Y=\frac{8g}{15.7g}*100\% \\\\Y=50.9\%[/tex]

Best regards.

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