Answer:
Protons = 28
Neutrons = 42
Explanation:
Alpha decay is one of radioactive decay in which the atomic nuclei can be illustrated by the emission or loss of helium particles of mass number 4 and proton number of 2
Because mass number is the sum of protons and neutrons, If a (hypothetical) atom with 30 protons and 44 neutrons undergoes alpha decay, 28 protons will be left in the nucleus and 42 neutrons will be left in the nucleus.
