Respuesta :
Answer:people are going to play a ball game. Each team has 3 players.
How many different team combinations are possible? 6C3 = 6!/(3!3!) = 20 possible
Step-by-step explanation:
Using the combination formula, it is found that 20 different team combinations are possible.
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- The order in which the players are selected is not important(Tre'Davious, Micah and Greg is the same team as Greg, Tre'Davious and Micah), and thus, the combination formula is used to solve this question.
Combination formula:
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by:
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
In this question:
- 3 people from a set of 6, thus:
[tex]C_{6,3} = \frac{6!}{3!(6-3)!} = 20[/tex]
20 combinations are possible.
A similar problem is given at https://brainly.com/question/24437717
