Respuesta :
Answer: [tex]CaSO_3.2H_2O[/tex]
Explanation:
To formulate the empirical formula, we need to follow some steps:
Step 1: Converting the given masses into moles.
Moles of [tex]CaSO_3[/tex] =[tex]\frac{\text{Given mass}}{\text{Molar mass }}=\frac{76.9g}{120g/mole}=0.64moles[/tex]
Moles of [tex]H_2O[/tex] = [tex]\frac{\text{Given mass}}{\text{Molar mass}}=\frac{23.1g}{18g/mole}=1.28moles[/tex]
Step 2: Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated.
For [tex]CaSO_3[/tex] = [tex]\frac{0.64}{0.64}=1[/tex]
For [tex]H_2O[/tex] = [tex]\frac{1.28}{0.64}=2[/tex]
Step 3: Taking the mole ratio as their subscripts.
The ratio of [tex]CaSO_3[/tex] : [tex]H_2O[/tex] is 1: 2
Hence, the formula for the given compound is [tex]CaSO_3.2H_2O[/tex]
What is the molar mass of the anhydrous compound? Answer using four significant figures.
Answer if on Edge:
120.15 g/mol
