The graph of the given equation and the orientation of its transverse axis is required.
The graph is attached.
The orientation of transverse axis will be horizontal.
The given equation is
[tex]\dfrac{x^2}{4}-\dfrac{y^2}{1}=1\\\Rightarrow \dfrac{x^2}{2^2}-\dfrac{y^2}{1^2}=1[/tex]
The given equation is of the form
[tex]\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1[/tex]
The transverse axis will be the [tex]x[/tex] axis between the points [tex](-2,0)[/tex] and [tex](2,0)[/tex]
So, the orientation of transverse axis will be horizontal.
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