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In simplest radical form, what are the solutions to the quadratic equation 0 = –3x2 – 4x + 5?

Respuesta :

HomertheGenius
- 3 x² - 4 x + 5 = 0
[tex] x_{1} = \frac{4+ \sqrt{16+60} }{-6} = \frac{4+8.718}{-6} [/tex]
x1 = -2.12
[tex] x_{2} = \frac{4-8.718}{-6} [/tex]
x2= 0.786

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