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An aqueous solution that contains 285 ppm of potassium nitrate 1KNO32 is being used to feed plants in a garden. What volume of this solution is needed to prepare 2.0 L of a solution that is 75 ppm in KNO3

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dsdrajlin

Answer:

0.53 L

Explanation:

Given data

  • Initial concentration (C₁): 285 ppm
  • Initial volume (V₁): ?
  • Final concentration (C₂): 75 ppm
  • Final volume (V₂): 2.0 L

We can find the required volume of the initial solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 75 ppm × 2.0 L / 285 ppm

V₁ = 0.53 L

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