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How much heat is needed to raise the temperature of 100.0 g of water by 50.0°C? (Water’s specific heat is 4.18 J/g•°C)

Respuesta :

Answer:

20900 J

Explanation:

  1. Formula:Q=m×c×△θ
  2. m=100g
  3. c=4.18
  4. △θ=50°C
  5. Q=100×4.18×50=20900J

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