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A car traveling 75km/h slows down at a constant 0.50m/s^2 just by letting up the gass. a: calculate the distance the car coasts before it stops, b the time it takes to stop, and the distance it travels during the first and fifth seconds

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Answer:

d = vi * t + ½ * a * t^2, a = -0.5  

d5 = 20.8 * 5 – ½ * 0.5 * 5^2 = 91.5 m  

d6 = 20.8 * 6 – ½ * 0.5 * 6^2 =  106.8m

d6 – d5 = 15.3 m  

Explanation:

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