Answer:
0.670L is the volume for the concentrated solution
Explanation:
There is an element that indicates the relation between Molarity of concentrated solution with Molarity of diluted solution or their volumes.
This is the dilution factor.
We can apply like this:
Molarity of concentrated / Molarity of diluted = Volume of diluted / Vol. conc.
We replace data: 0.235 M / 0.18 M = 0.872L / Volume of concentrated
1.30 = 0.872L / Volume of concentrated
Volume of concentrated = 0.872L / 1.30
Volume of concentrated = 0.670L
Answer:
The volume of the stock solution = 0.053L
Explanation:
Step 1: Data given
Concentration of the stock solution = 0.235 M Ca(NO3)2
Concentration of the diluted solution =0.18 M Ca(NO3)2
Volume of the diluted solution = 0.872 L
Step 2: Calculate the volume of the stock solution
C1*V1 = C2*V2
⇒with C1 = the concentration of the stock solution = 0.235 M Ca(NO3)2
⇒with V1 = the volume of the stock solution = TO DETERMINED
⇒with C2 = the concentration of the diluted solution = 0.18 M Ca(NO3)2
⇒with V2 = the volume of the diluted solution = 0.872 L
1.5 M * V1 = 0.80 M * 0.10 L
V1 = 0.053 L
0.053 L of stock solution was used.
