Answer:
[tex]\theta=40^0[/tex]
Explanation:
The magnitude of the magnetic force is
[tex]F_m=evB\sin\theta[/tex]
To find the angle, we make [tex]\sin\theta[/tex] subject of the formula
[tex]\implies \sin\theta=\frac{F_m}{evB}=\frac{7.20\times 10^{-13}}{1.6\times 10^{-19}\times 3.90\times 10^6\times 1.80}[/tex]
[tex]\implies \sin\theta=0.641025641[/tex]
[tex]\therefore \theta=\sin^{-1}=39.8683^0\\\implies \theta\approxeq 40^0[/tex]
