Answer : The given compound belongs to ether and alcohol.
Explanation :
The chemical formula of the given compound is, [tex]C_5H_{12}O_2[/tex]
First we have to calculate the degree of unsaturation.
Formula used:
Degree of unsaturation = [tex]\frac{2C+2+N-X-H}{2}[/tex]
where,
C = number of carbon
H = number of hydrogen
N = number of nitrogen
X = number of halogen
Degree of unsaturation = [tex]\frac{2\times 5+2+0-0-12}{2}=0[/tex]
The degree of unsaturation is, 0 that means there is no double or triple bond in the compound only single bond is present between the atoms.
Thus, the given compound belongs to ether and alcohol.
