Answer:
[tex]\dot m = 4830.240 kg/s[/tex]
Explanation:
Given data:
height of water fall = 124.896 m
efficiency = 100%
Power = 5.776 MW
flow rate of water can be calculated as
[tex]\dot W = \eta \dot m gh[/tex]
where
[tex]\dot m [/tex]is flow rate of water
plugging all value in above relation
[tex]5.776 \times 10^6 = 1.00 \times \eta \times 9.81 \times 121.896[/tex]
solving for flow rate we get
[tex]\dot m = 4830.240 kg/s[/tex]